Download e-book for kindle: Algorithm Theory – SWAT 2006: 10th Scandinavian Workshop on by Raimund Seidel (auth.), Lars Arge, Rusins Freivalds (eds.)

By Raimund Seidel (auth.), Lars Arge, Rusins Freivalds (eds.)

ISBN-10: 354035753X

ISBN-13: 9783540357537

This publication constitutes the refereed court cases of the tenth Scandinavian Workshop on set of rules thought, SWAT 2006, held in Riga, Latvia, in July 2006.

The court cases comprises 36 revised complete papers awarded including three invited papers, addressing problems with theoretical algorithmics and functions in quite a few fields together with graph algorithms, computational geometry, scheduling, approximation algorithms, community algorithms, info garage and manipulation, combinatorics, sorting, looking out, on-line algorithms, optimization, amd more.

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Additional info for Algorithm Theory – SWAT 2006: 10th Scandinavian Workshop on Algorithm Theory, Riga, Latvia, July 6-8, 2006. Proceedings

Example text

Since M ≥ 22k , this will leave space for exactly one item of each size 2−j M + 1, j = i + 1, . . , . Thus, the bin gets filled to (1 − 2− )M + ε, where ε = (2i − 1) + ( − i) is the number of items packed in the bin. This number is increasing with i, and starting with the second smallest items, the bin gets filled −1 to (1 − 2− )M + 2 −1 . Thus, since 1 − 2− + 2M < α, FFDα will start with the smallest items, using i=1 2in−1 bins. The (nonpolynomial) algorithm, Knapsack, that simply fills each bin as much as possible (considering all possible combinations of items) will behave as FFDα on the sequences of the proof of Theorem 7.

The purpose of this partition into types is that if the load caused by the small intervals is very low, then opening a color of capacity 1 right away might be an overkill for the small intervals. Specifically, we want to show an absolute competitive ratio of 4, which would be impossible if a unit capacity color was opened immediately. Lemma 6. The total cost of the colors used for small requests is at most 4·OPT. Proof. If there is no type 2 small request, then the claim holds since the doubling procedure is a 4-competitive algorithm.

Obviously, all items y, such that bo (y) = b , fit in the bin b . For any two chains, x0 , . . , x and y0 , . . , ym , x = ym , since no two chains intersect. In addition, all items on a chain from some x are at least as large as x. Hence, for any b ∈ L, |b| ≥ x | b (x)=b |x| and thus, e(L) + s(L) ≥ s(F < ). (2) Most bins in L are filled to at least α: Consider two bins, b, b ∈ L, where b occurs before b and FFDα fills both with at least two items, but to less than α full. Let x and y be two items in b .

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Algorithm Theory – SWAT 2006: 10th Scandinavian Workshop on Algorithm Theory, Riga, Latvia, July 6-8, 2006. Proceedings by Raimund Seidel (auth.), Lars Arge, Rusins Freivalds (eds.)

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